#1. 1. Write a python function that returns the index of the smallest element in a list of integers. If the number of such elements is greater than 1, return the smallest index. 



def indexOfSmallestElement(lst):
    print("index of smallest element:",list1.index(min(list1)))
    


list1=[]
n= int(input("Enter number of elements in the list:"))

for i in range(0,n):
   lst=input()
   list1.append(lst)
print("list1:",list1)    
indexOfSmallestElement(list1)
    
    

Enter number of elements in the list:6
2
3
4
5
6
4
list1: ['2', '3', '4', '5', '6', '4']
index of smallest element: 0

#2.Write the python function mostCommonName

list1=[]
list2=[]

n= int(input("Enter number of elements in the list:"))

for i in range(0,n):
   lst=input()
   list1.append(lst)
print("input list1:",list1) 

for i in list1:
     if(list1.count(i) > 1):
         list2.append(i) 
        
print(set(list2))        
    

Enter number of elements in the list:6
reva
tre
tre
reva
tgh
yhk
input list1: ['reva', 'tre', 'tre', 'reva', 'tgh', 'yhk']
{'tre', 'reva'}

#3.Write the python function isPalindromicList(a) that takes a list and returns True if it is the same forwards as backwards and False otherwise.

def isPalindromicList(list1):
    flag=0
    list2=[]
    list2.extend(list1)
    list1.reverse()
    for i in range(len(list1)):
        if list1[i] == list2[i]:
            i+=1
            flag=1
        else:
            flag=0
            break
            
    if flag == 1:
        return True
    else:
        return False
            

list1=[]
n= int(input("Enter number of elements in the list:"))

for i in range(0,n):
   lst=input()
   list1.append(lst)


print(isPalindromicList(list1))

Enter number of elements in the list:5
1
2
1
2
1
True