Chef is a software developer, so he has to switch between different languages sometimes. Each programming language has some features, which are represented by integers here. Currently, Chef has to use a language with two given features A and B. He has two options --- switching to a language with two features A1 and B1, or to a language with two features A2 and B2. All four features of these two languages are pairwise distinct. Tell Chef whether he can use the first language, the second language or neither of these languages (if no single language has all the required features)¶

The first and only line of each test case contains six space-separated integers A,B,A1,B1,A2,B2. For each test case, print a single line containing the integer 1 if Chef should switch to the first language, or 2 if Chef should switch to the second language, or 0 if Chef cannot switch to either language.¶

In [ ]:
def solve():
    a, b, a1, b1, a2, b2 = int(input('Enter 6 numbers: '))
    if(a>b):
        temp = a
        a = b
        b = temp
    if(a1> b1):
        temp = a1
        a1=b1
        b1=temp
    if(a2>b2):
        temp=a2
        a2=b2
        b2=temp
        
    if (a==a1 && b==b1):
        print(1)
    elif(a == a2 && b==b2):
        print(2)
    else:
        print(0)
        
solve()

You have prepared four problems. The difficulty levels of the problems are A1,A2,A3,A4 respectively. A problem set comprises two problems and no two problems in a problem set should have the same difficulty level. A problem can belong to at most one problem set. Find the maximum number of problem sets you can create using the four problems.¶

In [ ]:
t=int(input())
l=[]
s=set()
while(t>0):
    for i in range(0,4):
        i=int(input())
        s.add(i)
        l.append(i)
    #print(len(s))
    if(len(s)==4):
        print("2")
    elif(len(s)==1):
        print("0")
    elif(len(s)==3):
        print("1")
    elif(len(s)==2):
        b=0
        c=l[0]
        for i in range(0,3):
            if(c==l[i+1]):
                b=b+1
                #print(b)
        if(b==1):
            print("2")
        else:
            print("1")
    s.clear()
    l.clear()
    t=t-1
In [ ]: