PROGRAM TO FIND OUT VALUE OF 20, IF PRESENT REPLACE IT WITH 200 AND ONLY UPDATE THE FIRST OCCURRENCE OF AN ITEM¶

In [13]:
lst1 = [5,10,15,20,25,50,20]
lst1[3] = 200
print(lst1)

[5, 10, 15, 200, 25, 50, 20]

REMOVE THE OCCURRENCE OF ITEM 20¶

In [6]:
mylist = [5,20,15,20,25,50,20]
rem_num = 20

for item in mylist:
    if(item == rem_num):
        mylist.remove(rem_num)
print(mylist)

[5, 15, 25, 50]

TO ITERATE BOTH LISTS SIMULTANEOUSLY AND DISPLAY ITEMS FROM LIST1 IN ORIGINAL ORDER AND ITEMS IN LIST2 IN DESCENDING ORDER¶

In [7]:
list1 = [10,20,30,40]
list2 = [100,200,300,400]

for x,y in zip(list1,list2[::-1]):
    print(x,y)

10 400
20 300
30 200
40 100
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